((x^2)-(2x))=15

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Solution for ((x^2)-(2x))=15 equation:


Simplifying
((x2) + -1(2x)) = 15
(x2 + -1(2x)) = 15

Remove parenthesis around (2x)
(x2 + -1 * 2x) = 15

Multiply -1 * 2
(x2 + -2x) = 15

Reorder the terms:
(-2x + x2) = 15

Remove parenthesis around (-2x + x2)
-2x + x2 = 15

Solving
-2x + x2 = 15

Solving for variable 'x'.

Reorder the terms:
-15 + -2x + x2 = 15 + -15

Combine like terms: 15 + -15 = 0
-15 + -2x + x2 = 0

Factor a trinomial.
(-3 + -1x)(5 + -1x) = 0

Subproblem 1

Set the factor '(-3 + -1x)' equal to zero and attempt to solve: Simplifying -3 + -1x = 0 Solving -3 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1x = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1x = 0 + 3 -1x = 0 + 3 Combine like terms: 0 + 3 = 3 -1x = 3 Divide each side by '-1'. x = -3 Simplifying x = -3

Subproblem 2

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Solution

x = {-3, 5}

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